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# Find an equation of the plane through the point parallel to the plane 0x 9 yz 4 4

Parallel and perpendicular line calculator. This calculator find and plot equations of parallel and perpendicular to the given line and passes through given point. The calculator will generate a.

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Is the prediction reliable? Explain. 32. Write the standard form of the equation of the line that passes through the point at (4, 2) and is parallel to the line whose equation is y ϭ 2x Ϫ 4. (Lesson 1-5) 33. Sports During a basketball game, the two highest-scoring players scored 29 and 15 points and played 39 and 32 minutes, respectively. (Lesson 1-3) a. Write an ordered pair of. Equation () is a normalization term, and points with $$x_0=x_1=x_2=x_3=0$$ do not represent Euclidean transformations; they form the 3-dimensional exceptional generator contained in $$S_6^2$$.The points on $$S_6^2$$ are called kinematic image points of the corresponding displacement, and the seven-dimensional projective space is called kinematic.

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4 Chapter 23 Solutions *23.8 Let the third bead have charge Q and be located distance x from the left end of the rod. This bead will experience a net force given by F = k e()3q Q x2 i + k e()q Q ()d − 2 ()−i The net force will be zero if 3 x2 1 ()d − 2, or d −x = x 3 This gives an equilibrium position of the third bead of x = 0.634d The equilibrium is stable if the third bead has.

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results on sketches of properly oriented elements. xy Ox PROBLEMS 7.4-18 through 7.4-25 Similar Homework Help Questions Problem 73-2 An element in plane stress is subjected to stresses σ.-105 MPa, dry-75 MPa, and Try-25 MPa (see the figure for Prob. 7.2-2) Determine the principal stresses and show them on a sketch of a properly oriented element. An element in.

ANSWER : - (a) The equation of the plane is z = 2 or 0 x + 0 y + z = 2 (1) The direction ratios of normal are 0, 0, and 1. This is of the form lx + my + nz = d, where l , m , n are the direction cosines of normal to the plane and d is the distance of the perpendicular drawn from the origin. The Exercise 11.3 of NCERT Solutions for Class 12 Maths Chapter 11- Three Dimensional Geometry is based on the following topics: Plane. Equation of a plane in normal form. Equation of a plane perpendicular to a given vector, passing through given point. Equation of a plane passing through three non collinear points.

A calculator and solver to find the equation of a line, in 3D, that passes through a point and is perpendicular to a given vector. As many examples as needed may be generated interactively.

3.3.4: Find critical points and determine type: f(x;y) =x2 +y2 +3xy; ∇f(x;y)=(2x+3y;2y+3x): ∇fis 0 =(0;0) only when (x;y)=(0;0), so it’s the only critical point. f xx≡2; f xy≡3; f yx≡3; f yy≡2: The Hessian matrix (anywhere, and in particular at (0;0)) is: „ 2 3 3 2 ‚; with determinant D=49 =−5 <0, so (0;0) is a saddle point. 3.3.10: Find critical points and determine.

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Find an equation for the plane through point (2,-1,5) that is parallel to both the vectors { v_1=i+2k ,and ,v_2=j-3k } Find the equations for the planes described below. (a) Plane 1: passing through the point (2, -1, 4) with normal vector langle {-1, 2, -3} rangle . (b) Plane 2: passing through these three points ; If L :< x , y , z >=< x p , y p , z p > + t < x D , y D , z D >.

Find an equation of the plane consisting of all points that are equidistant from (-3,4,4) and (-1,4,-3) , and having 2 as the coefficient of x. Find the point in the first octant where the tangent.

Find the equation of the sphere passing through the points 0,0,0,0,1,1, 1,2,0 1,2,3 and . (N/D 2011)(AUT) 2. Obtain the equation of the sphere having the circle x y z2 2 2 9, x y z 3 as a great circle. (Jan 2009) 3. Obtain the equation of the sphere having the circle x y z y z2 2 2 10 4 8 0, x y z 3 as the greatest circle. (Jan 2012),(M/J 2012) Engineering Mathematics Material 2013 4.. direction ratio = (x2 – x1, y2 – y1, z2 – z1) Since the line is parallel to the given axis . Therefore, the cross-product of and is 0 which is given by: where, d, e, and f are the coefficient.

z = x2 +y2 and the plane z = 4, with outward orientation. (a) Find the surface area of S. Note that the surface S consists of a portion of the paraboloid z = x2 +y2 and a portion of the plane z = 4. Solution: Let S1 be the part of the paraboloid z = x2 + y2 that lies below the plane z = 4, and let S2 be the disk x2 +y2 ≤ 4, z = 4. Then.

. A line parallel to it would have the same slope and will also be a vertical line perpendicular to the x-axis. As the line passes through the point (2, -1) its equation is x = 2.

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Let be a surface with equation , ,S F x y z k is a level surface of a function of SFthree variables Let , , be a point on .P x y z S 0 0 0 Let be any curve that lies on the surfa ce and passes through the point . CS P Let defined by , ,C t x t y t z tr Let be the parameter value correspondintP0 g to.

EQUATION (from Lat. aequatio, aequare, to equalize), an expression or statement of the equality of two quantities. Mathematical equivalence is denoted by the sign =, a symbol invented by Robert Recorde (1510-1558), who considered that nothing could be more equal than two equal and parallel straight lines. An equation states an equality existing.

Two-sheeted Hyperboloid x 2 + y 2 − z 2 = 0 Double Cone x 2 + y 2 − z 2 = 1 Single-sheeted Hyperboloid by taking c = − 1, 0, and 1. The two-sheeted hyperboloid and double cone are very important in physics, while the single sheeted hyperboloid is a favorite architectural device - cooling towers etc - as is the hyperbolic paraboloid.

4. A circular wire loop 4 0 cm in diameter has 100-! resistance and lies in a horizontal plane. A uniform magnetic field points vertically downward, and in 2 5 ms it increases linearly from 5 .0 mT to 55 mT. Find the magnetic flux through the loop at (a) the beginning and (b) the end of the 2 5 ms period. (c) What is the loop current during.

image (C) displays the data in array C as an image. Each element of C specifies the color for 1 pixel of the image. The resulting image is an m -by- n grid of pixels where m is the number of rows and n is the number of columns in C. The row and column indices of the elements determine the centers of the corresponding pixels. Free perpendicular line calculator - find the equation of a perpendicular line step-by-step.

Let be a surface with equation , ,S F x y z k is a level surface of a function of SFthree variables Let , , be a point on .P x y z S 0 0 0 Let be any curve that lies on the surfa ce and passes through the point . CS P Let defined by , ,C t x t y t z tr Let be the parameter value correspondintP0 g to.

Find the equation of the following planes. (a) the plane passing through the points (−1, 1, −1), (1, −1, 2), and (4, 0, 3) (b) the plane passing through the point (0, 1, 2) and containing the line x = y = z (c) the plane containing the lines L1 : x = 1 + t, L2 : x = 2 − s, y = 2 − t, y = 1 + 2s, z = 4t z =4+s 4. Find the intersection.

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Submitting a report will send us an email through our customer support system. Submit report Close /lp/spie/measurement-of-large-plane-surface-shapes-by-connecting-small-aperture-oIaoCCsBFw.

One surface of the slab is at x = d/2. This surface, call it the front surface, is a plane which is parallel to the yz-plane. The other surface, call it the rear surface, of the slab is at x = -d/2. This surface is also parallel to the yz-plane. Mid way between the front and back surfaces, at x = 0, is the yz-plane. Feb 20, 2012 #7 Tsunoyukami 215.

To evaluate the surface integral in Equation 1, we approximate the patch area ∆S ij by the area of an approximating parallelogram in the tangent plane. , 11 ( , , ) lim ( ) mn ij ij mn S ij f x y z dS f P S of ³³ '¦¦ Equation 1 . SURFACE INTEGRALS In our discussion of surface area in Section 16.6, we made the approximation ∆S ij ≈ |r u x r v | ∆u ∆v where: are the tangent vectors.

Oct 07, 2014 · 9 92 4(1)(6) = 2(1) 9 57 = 2 9 + 57 9 57 Thus, x =,. 2 2. 67. 69. (q + 2) 2 = 2 4q 7. b b 2 4ac 2a. 0 = x 2 21x 0 = x(x 21) x = 0 or x = 21 Only x = 21 checks. 5 x 2 + 13 x + 6 = 4 x 2 + 4 x. 65. x+4. 9 x + 36 = x 2 12 x + 36. 2 x2 + 4 x + 3x2 + 9 x + 6 = 4 x2 + 4 x. x= (3 = 7 2 6. z + 3 = 3z + 1. 71. z +3) =(2. 3z + 1. z + 3 = 3z + 2 3z + 1 2 ....

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If A 1 x + B 1 y + C 1 z + D 1 = 0 and A 2 x + B 2 y + C 2 z + D 2 = 0 are a plane equations, then angle between planes can be found using the following formula. cos α = |A 1 ·A 2 + B 1 ·B 2 + C 1 ·C 2 | √ A 1 2 + B 1 2 + C 1 2 √ A 2 2 + B 2 2 + C 2 2. See also - library: angle between two planes. You can input only integer numbers, decimals or fractions in this online calculator (-2.4.

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is the distance between given points A and B. If, for example, in the above equation of a line through two points in a space, we take that z coordinate of both given points is zero, we obtain known equation of a line through two points in a coordinate plane, i.e., and at the same time, it is the equation of the orthogonal projection of a line in 3D space onto the xy coordinate plane.

3 Find the Equation of a Vertical Line 4 Use the Point-Slope Form of a Line; Identify Horizontal Lines 5 Use the Slope-Intercept Form of a Line 6 Find the Equation of a Line Given Two Points 7 Graph Lines Written in General Form Using Intercepts 8 Find Equations of Parallel Lines 9 Find Equations of Perpendicular Lines 1.4 Circles 1 Write the.

point A (1,3,-2) act as origin point B which is on the plane has point (3,-2,1) from three equations we can get vector of a plane <1,4,-2> then point AB vector is B-A = (2,-5,0) to get.

Solution for Parallel planes Determine the equation of the plane parallel to the xz-plane passing through the point (2, -3, 7). Skip to main content. close. Start your trial now! First week only.

Learning Objectives. 2.5.1 Write the vector, parametric, and symmetric equations of a line through a given point in a given direction, and a line through two given points.; 2.5.2 Find.

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The equation of a circle is (x − a)2 + (y − b)2 = r2 where a and b are the coordinates of the center (a, b) and r is the radius. The invention of Cartesian coordinates in the 17th century by René Descartes ( Latinized name: Cartesius) revolutionized mathematics by providing the first systematic link between Euclidean geometry and algebra.

Find an equation of the plane. The plane through the point (4, 0, 1) and perpendicular to the line x = 9t, y = 7 − t, z = 3 + 8t - 14579321. soyeb1303 soyeb1303.

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If A 1 x + B 1 y + C 1 z + D 1 = 0 and A 2 x + B 2 y + C 2 z + D 2 = 0 are a plane equations, then angle between planes can be found using the following formula. cos α = |A 1 ·A 2 + B 1 ·B 2 + C 1 ·C 2 | √ A 1 2 + B 1 2 + C 1 2 √ A 2 2 + B 2 2 + C 2 2. See also - library: angle between two planes. You can input only integer numbers, decimals or fractions in this online calculator (-2.4.

z = x2 +y2 and the plane z = 4, with outward orientation. (a) Find the surface area of S. Note that the surface S consists of a portion of the paraboloid z = x2 +y2 and a portion of the plane z = 4. Solution: Let S1 be the part of the paraboloid z = x2 + y2 that lies below the plane z = 4, and let S2 be the disk x2 +y2 ≤ 4, z = 4. Then.

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This online calculator will help you to find equation of a plane. Using this online calculator, you will receive a detailed step-by-step solution to your problem, which will help you understand the. 166. "If through a point 0, within a given triangle AB C, three lines be drawn respectively parallel to the sides of the triangle; viz., GE parallel to BC, FH, to AB and DT to AC, and there is given, GOXOE + FO X0H+ DOXOT; to find the locus of 0 by plane geometry." SOLUTION BY PEOF. W. P. CASEY, SAN FRANCISCO, CAL. Construction. Let X be the.

at the point c. Evolute 1) Find the equation of evolute of the parabola y ax2 4. 2) Find the equation of evolute of the parabola x ay2 4. 3) Find the equation of the evolute of the ellipse 22 22 1 xy ab . 4) Find the equation of the evolute of the hyperbola 22 22 1 xy ab . 5) Show that the evolute of the cycloid xa ( sin )TT, ya (1 cos )T is.

Misc 8 Find the equation of the plane passing through (a, b, c) and parallel to the plane 𝑟 ⃗ . (𝑖 ̂ + 𝑗 ̂ + 𝑘 ̂) = 2.The equation of plane passing through (x1, y1, z1) and perpendicular to a line with.

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Partial derivatives and diﬀerentiability (Sect. 14.3). I Partial derivatives and continuity. I Diﬀerentiable functions f : D ⊂ R2 → R. I Diﬀerentiability and continuity. I A primer on diﬀerential equations. Diﬀerentiability and continuity. Recall: The graph of a diﬀerentiable function f : D ⊂ R2 → R is approximated by a plane at every point in D.

Jun 03, 2020 · I used the invariant point (0, 0) and symmetry to complete the graph of y 5 ( 15 x) 2. I knew from the absolute value signs that the parent function was the absolute value function. 1 5 4. The point that I knew that the stretch factor was 0.25 originally was (1, 1) corresponded to the new point (4, 1).. 21. evaluate 4y+x for y=2,x=3 22. 2x+5=9 23. 4y+x, y=2,x=3 24. Rational expression - (2x+8)/ (3x+1)- (x+4)/ (7x+1) 25. Polynomial - factor x^2-3x+2 26. Polynomial - expand (x+3) (x+2) 27. Polynomial - expand 102^2 28. complete the square 3x^2+5x+4 29. is perfect square x^2+4x+4 30. Perfect square trinomial - missing first term 12x^2+9 31.

Find the equation of a parallel line step-by-step. Line Equations. Functions. Arithmetic & Composition. Conic Sections. Transformation New. full pad ». x^2. x^ {\msquare}.

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U = −p·E (2.9) 2.1.4 Electric Field Lines Oftentimes it is useful for us to get an overall visual picture of the electric ﬁeld due to a particular distribution of charge. It is useful make a plot where the little arrows represent- ing the direction of the electric ﬁeld at each point are joined together, forming continuous (directed) “lines”. These are the electric ﬁeld lines for.

The last row corresponds to the equation 0x 1 + 0x 2 + 0x 3 + 0x 4 = 1 from which it is evident that the system is inconsistent. Solution (b) The last row corresponds to the equation 0x 1 + 0x 2 + 0x 3 + 0x 4 = 0 which has no effect on the solution set. In the remaining three equations the variables x 1 , x 2 , and x 3 correspond to leading 1. Mathematics of 3-Dimensional Geometry for class 6 - 12 CBSE, ICSE, State board with free sectional tests, mock exams, solved papers of NDA, Sainik Schools, CAT, MAT, XAT, SNAP, IIT JEE for previous years.

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1) Intensity of unpolarized light incident on linear polarizer is reduced by half . I1= I0/ 2 I = I0 I1 I2 2) Light transmitted through first polarizer is vertically polarized. Angle between it and second polarizer is θθθθ=90º . I2= I1cos2(90º) = 0 4/20/2011 10 unpolarized light E1 45° I = I0 TA TA 90° TA E0 I3 B1 Law of Malus Example.

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9.4.10 Write the given system as a set of scalar equations x0= 2 1 1 3 x + et t 1 This becomes the equations x0 1= 2x + x 2 + tet x0 2= x 1 + 3x + et 9.4.16 Determine whether the given vector functions are linearly dependent or independent on the interval (1 ;1) sint cost ; sin2t cos2t We compute the Wronskian det sint sin2t cost cos2t.

Equation () is a normalization term, and points with $$x_0=x_1=x_2=x_3=0$$ do not represent Euclidean transformations; they form the 3-dimensional exceptional generator contained in $$S_6^2$$.The points on $$S_6^2$$ are called kinematic image points of the corresponding displacement, and the seven-dimensional projective space is called kinematic.

Oct 07, 2014 · 9 92 4(1)(6) = 2(1) 9 57 = 2 9 + 57 9 57 Thus, x =,. 2 2. 67. 69. (q + 2) 2 = 2 4q 7. b b 2 4ac 2a. 0 = x 2 21x 0 = x(x 21) x = 0 or x = 21 Only x = 21 checks. 5 x 2 + 13 x + 6 = 4 x 2 + 4 x. 65. x+4. 9 x + 36 = x 2 12 x + 36. 2 x2 + 4 x + 3x2 + 9 x + 6 = 4 x2 + 4 x. x= (3 = 7 2 6. z + 3 = 3z + 1. 71. z +3) =(2. 3z + 1. z + 3 = 3z + 2 3z + 1 2 ....

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Q10 : Find the vector equation of the plane passing through the intersection of the planes and through the point (2, 1, 3) Answer : The equations of the planes are The equation of any plane through the intersection of the planes given in equations (1) and (2) is given by,, where The plane passes through the point (2, 1, 3). Therefore, its.

Equation of a Plane Passing through Two Parallel Lines . Let the plane pass through parallel lines r → = a → + λ b → and r → = c → + μ b →. As shown in the diagram, for any position of R in the plane , vectors R A →, A C → and b → are coplanar. Then [ r → − a → c → − a → b →] = 0, which is the required equation.

Calculus questions and answers. Find the equation of the plane that is parallel to the vectors \ ( \langle 1,0,2\rangle \) and \ ( \langle 0,3,2\rangle \), passing through the point \ ( (2,0,-3) \). The equation of the plane is (Type an equation using \ ( x, y \), and \ ( z \) as the variables) Question: Find the equation of the plane that is.

Write the equation of the plane parallel to XY-plane and passing through the point (4,-2,3).

4. (a) Find the equation of a plane perpendicular to the vector ~i −~j + ~k and passing through the point (1,1,1). (b) Find the equation of a plane perpendicular to the planes 3x + 2y − z = 7 and x−4y +2z = 0 and passing through the point (1,1,1). Solution. (a) The equation of the plane with normal vector~i−~j+~k and passing through. Jun 03, 2020 · I used the invariant point (0, 0) and symmetry to complete the graph of y 5 ( 15 x) 2. I knew from the absolute value signs that the parent function was the absolute value function. 1 5 4. The point that I knew that the stretch factor was 0.25 originally was (1, 1) corresponded to the new point (4, 1).. Equation of a Plane Passing through Two Parallel Lines . Let the plane pass through parallel lines r → = a → + λ b → and r → = c → + μ b →. As shown in the diagram, for any position of R in the plane , vectors R A →, A C → and b → are coplanar. Then [ r → − a → c → − a → b →] = 0, which is the required equation. The plane through the point (4, -9, -8) and parallel to the plane 4x - y - z = 3. Equation of the Plane: The standard form of the equation of the plane is represented as, ax + by + cz = D.

It is known that the line which passes through point A and parallel to b is given by r = a + λb, where λ is a constant. => r = (i + 2j + 3k) + λ (3i + 2j – 2k) This is the required equation of the line. Question 5:.

Oct 29, 2013 · 2. FLEXURAL MEMBERS 2.2 ASSUMPTJONS . The basic assumptions in the design of flexur&lmembers for the limit state of collapse are fcivenbelow (see 37.2 of the Code): 4 Plane sections normal to the axis of the member remain plane after bending..

8. Find the equation of the locus of a point the supn of the squares of whose distances from (3, 0) and (- 3, 0) always equals 68. Plot the locus. Ans. The circle x2 + y2 = 25. 9. Find the equation of the locus of a point which moves so that its distances from (8, 0) and (2, 0) are always in a constant ratio equal to 2. Plot the locus. Ans. The.

Find an equation of the plane. The plane through Oh no! Our educators are currently working hard solving this question. In the meantime, our AI Tutor recommends this similar expert step-by-step video covering the same topics. View Video. Like. Report. View Text Answer. Linh V. Numerade Educator. Like. Report. Jump To Question Problem 1 Problem 2 Problem 3 Problem. Learning Objectives. 4.6.1 Determine the directional derivative in a given direction for a function of two variables.; 4.6.2 Determine the gradient vector of a given real-valued function.; 4.6.3 Explain the significance of the gradient vector with regard to direction of change along a surface.; 4.6.4 Use the gradient to find the tangent to a level curve of a given function. at the point c. Evolute 1) Find the equation of evolute of the parabola y ax2 4. 2) Find the equation of evolute of the parabola x ay2 4. 3) Find the equation of the evolute of the ellipse 22 22 1 xy ab . 4) Find the equation of the evolute of the hyperbola 22 22 1 xy ab . 5) Show that the evolute of the cycloid xa ( sin )TT, ya (1 cos )T is.

through equation (1). This means that w e are free to assign a v alue only one of the co ordinates t ypical p oin ton C; the other co ordinate m ust b e determined from the equation of the circle. F or this reason w esa y C has one degree of freedom. Cho osing x as the parameter for C,w e see from (1) that y = p 4 x 2; where the p ositiv e. Electric field. To help visualize how a charge, or a collection of charges, influences the region around it, the concept of an electric field is used. The electric field E is analogous to g, which we called the acceleration due to gravity but which is really the gravitational field. Everything we learned about gravity, and how masses respond to.

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81 9 = 4 2 81 9 = 49 7 1 32 9 9 − 1 = − 4 49 2 7 1 1 5 45 = 9 − = 9 = 2 7 14 14 1/31/2018 11:28:54 AM Number Systems 1.23 Test your concepts Very Short Answer Type Questions Directions for questions 1 to 9: State whether the following statements are true or false. 21. Which of the following sets is not closed under subtraction?.

We might as well label the point-trace situation as x;0;(y/z)(z/y) to express that the two degree-2 nodes can be thought of as belonging to any two perpendicular axes in yz plane. Cyclodome As all 4 nodes of the cyclodome are equivalent, it's rolling is very simple - it has only three possible configurations: 0xyz, 0yxz, and 0xzy. Each of these.

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through equation (1). This means that w e are free to assign a v alue only one of the co ordinates t ypical p oin ton C; the other co ordinate m ust b e determined from the equation of the circle. F or this reason w esa y C has one degree of freedom. Cho osing x as the parameter for C,w e see from (1) that y = p 4 x 2; where the p ositiv e. equation, which can be written between any two points in the flow field since the flow is irrotational. Thus, applying the Bernoulli equation between a point far from the body, where the pressure is p0 and the velocity is U, and some arbitrary point with pressure p and velocity V, it follows that p0 ϩ 1 ␳U 2 ϭ p ϩ 1 ␳V 2 (6.102) 2 2. resulting conic sections in the given plane. Given an equation for a quadric surface, be able to recognize the type of surface (and, in particular, its graph). PRACTICE PROBLEMS: For problems 1-9, use traces to identify and sketch the given surface in 3-space. 1. 4x 2+ y2 + z = 4 Ellipsoid 1. 2. 2x 2y2 + z = 1 Hyperboloid of 2 Sheets 3. 4x 2+ 9y 36z2 = 36 Hyperboloid of 1. It is known that the line which passes through point A and parallel to b is given by r = a + λb, where λ is a constant. => r = (i + 2j + 3k) + λ (3i + 2j – 2k) This is the required equation of the line. Question 5:.

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Answer to: Find the linear equation of the plane through the point (2.9, 10) and parallel to the plane x+3y+5z+4=0 By signing up, you'll get.

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0x + (—by) +12bz — 2b = 0. x - y +12z —2 = 0. 2x-2y + z-4 = 0. Therefore, the equation of the plane with the three non-collinear points A, B, and C is. 2x-2y + z-4 = 0. Example 2: S (0,0,2),.